Science & Engineering
Hooke's Law Calculator - F = kx Spring Force
Solve Hooke's Law F = kx for force, spring constant, or extension. Also calculates elastic potential energy stored in the spring (U = ½kx²).
Force F (lbf)
20.0000
Spring const k (lbf/ft)
200.0000
Extension x (ft)
0.1000
Elastic PE (ft·lbf)
1.0000
Hooke's Law Formula
F = k × x - The restoring force of a spring is proportional to its displacement from equilibrium. This holds within the elastic limit; beyond it the spring permanently deforms.
Spring constant reference
| Spring type | Approximate k |
|---|---|
| Watch hairspring | ~10 N/m |
| Bungee cord | ~100 N/m |
| Stiff mattress spring | ~500 N/m |
| Mechanical keyboard switch | ~500–1,500 N/m |
| Car suspension spring | ~15,000–40,000 N/m |
Elastic potential energy
A compressed or stretched spring stores energy. The elastic potential energy is:
PE = ½kx²
For example, a spring with k = 500 N/m compressed by 0.1 m stores PE = ½ × 500 × 0.01 = 2.5 joules. This energy is released when the spring returns to equilibrium - the basis of mechanical watches, spring-loaded toys, and retractable pens.
Elastic limit
Hooke's Law only holds within the elastic region of a material. Beyond the elastic limit (the yield point), the material deforms plastically and will not return to its original shape when the force is removed. On a stress-strain curve, the elastic region is the initial linear portion; the yield point marks where the curve begins to bend.
Real-world applications
- Shock absorbers: springs and dampers absorb road impacts in vehicles
- Seismic isolators: large springs decouple buildings from ground motion
- Mechanical keyboard switches: spring force determines actuation feel
- Vehicle suspension: spring constant is tuned for ride comfort vs. handling
- Medical devices: surgical retractors and stents use calibrated spring forces